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Na2[Sn(OH)6] + 8e → 2NaH + Sn + 2H2O + 4O2−

Reduction of sodium hexahydroxidostannate(IV) yields sodium hydride, tin, water, and oxide ion (Other reactions are here). This reaction is an oxidation-reduction reaction and is classified as follows:

Table of contents
  1. 1Reaction data
  2. 2Thermodynamic changes
  3. 3References
  4. 4Related reactions
  5. 5Related categories

Reaction data

Chemical equation

General equation

Reduction of reducible species
ReactantOxidizing agent + e
ProductReduction product

Oxidation state of each atom

Reactants

Chemical formulaNameCoefficientTypeType in general
equation
Na2[Sn(OH)6]Sodium hexahydroxidostannate(IV)1
Oxidizing
eElectron8
Electron

Products

Chemical formulaNameCoefficientTypeType in general
equation
NaHSodium hydride2
Reduced
SnTin1
Reduced
H2OWater2
O2−Oxide ion4

Thermodynamic changes

Thermodynamic data of reactants

Chemical formulaStandard enthalpy
of formation
ΔfH°
kJ · mol−1
Standard Gibbs
energy of
formation
ΔfG°
kJ · mol−1
Standard
molar entropy
S°
J · K−1 · mol−1
Standard molar
heat capacity at
constant pressure
Cp°
J · K−1 · mol−1
Na2[Sn(OH)6]
e

Thermodynamic data of products

Chemical formulaStandard enthalpy
of formation
ΔfH°
kJ · mol−1
Standard Gibbs
energy of
formation
ΔfG°
kJ · mol−1
Standard
molar entropy
S°
J · K−1 · mol−1
Standard molar
heat capacity at
constant pressure
Cp°
J · K−1 · mol−1
NaH (cr)-56.275[1]-33.46[1]40.016[1]36.401[1]
NaH (g)130.25[1]108.85[1]188.377[1]30.29[1]
Sn (cr)
white
0[1]0[1]51.55[1]26.99[1]
Sn (cr)
gray
-2.09[1]0.13[1]44.14[1]25.77[1]
Sn (g)302.1[1]267.3[1]168.486[1]21.259[1]
H2O (cr)
H2O (l)-285.830[1]-237.129[1]69.91[1]75.291[1]
H2O (g)-241.818[1]-228.572[1]188.825[1]33.577[1]
O2−
* (cr):Crystalline solid, (g):Gas, (l):Liquid

References

List of references

  1. 1