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SnF4 + 2Ba(OH)2 → 2BaF2 + Sn(OH)4

The reaction of tin(IV) fluoride and barium hydroxide yields barium fluoride and tin(IV) hydroxide. This reaction is an acid-base reaction and is classified as follows:

Table of contents
  1. 1Reaction data
  2. 2Thermodynamic changes
  3. 3References
  4. 4Related categories

Reaction data

Chemical equation

General equation

Oxidation state of each atom

Reactants

Chemical formulaNameCoefficientTypeType in general
equation
SnF4Tin(IV) fluoride1
Brønsted acid
Salt of weak base
Ba(OH)2Barium hydroxide2
Brønsted base
Strong base

Products

Chemical formulaNameCoefficientTypeType in general
equation
BaF2Barium fluoride2
Conjugate acid
Salt of strong base
Sn(OH)4Tin(IV) hydroxide1
Conjugate base
Weak base

Thermodynamic changes

Thermodynamic data of reactants

Chemical formulaStandard enthalpy
of formation
ΔfH°
kJ · mol−1
Standard Gibbs
energy of
formation
ΔfG°
kJ · mol−1
Standard
molar entropy
S°
J · K−1 · mol−1
Standard molar
heat capacity at
constant pressure
Cp°
J · K−1 · mol−1
SnF4
Ba(OH)2 (cr)-944.7[1]
Ba(OH)2 (g)-586[1]
Ba(OH)2 (cr)
1 hydrate
-1248.5[1]
Ba(OH)2 (cr)
3 hydrate
-1849.3[1]
Ba(OH)2 (cr)
8 hydrate
-3342.2[1]-2792.8[1]427[1]
* (cr):Crystalline solid, (g):Gas

Thermodynamic data of products

Chemical formulaStandard enthalpy
of formation
ΔfH°
kJ · mol−1
Standard Gibbs
energy of
formation
ΔfG°
kJ · mol−1
Standard
molar entropy
S°
J · K−1 · mol−1
Standard molar
heat capacity at
constant pressure
Cp°
J · K−1 · mol−1
BaF2 (cr)-1207.1[1]-1156.8[1]96.36[1]71.21[1]
BaF2 (g)-818.0[1]-828.4[1]300.98[1]53.76[1]
BaF2 (ai)-1202.90[1]-1118.35[1]-18.0[1]
Sn(OH)4 (cr)
precipitated
-1110.0[1]
* (cr):Crystalline solid, (g):Gas, (ai):Ionized aqueous solution

References

List of references

  1. 1